1/x-4-1/x+4+2x/x^2-16

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Solution for 1/x-4-1/x+4+2x/x^2-16 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x-(1/x)+(2*x)/(x^2)-16-4+4 = 0

1/x-x^-1+(2*x)/(x^2)-16-4+4 = 0

2*x^-1 = 16 // : 2

x^-1 = 8

-1 < 0

1/(x^1) = 8 // * x^1

1 = 8*x^1 // : 8

1/8 = x^1

x = 1/8

x = 1/8

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